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  • how were the duplicate reads generated?

    Hi Guys,
    I am doing some chip-seq assay. I am wondering how the duplicate reads were generated.
    I know the sonication will generate random fragments. However, there is a step of 18 cycles PCR to amplify the library DNA. So, for each fragment, there should be 18 copies. i.e. each fragments should be ideally duplicate 18 times. If this is the case, why we need to remove them? and why we generally can not see 18 copies of the same reads after mapping?

    Thank you.

    -Q

  • #2
    You need to read up on PCR. Moving this to general.

    Comment


    • #3
      ECO,
      I have done PCR for years. But I still don't know what I was missing.
      PCR was used to amplify template, and this is not a random priming; and of course, the final result will contain similar copies of template, i.e for every template which was amplified should have at least one duplicate read. Why people said we should see very small amount of duplicate reads?
      Could you elaborate on this? Really confused.
      Thank you.
      -Q
      Last edited by qiudao; 10-18-2011, 07:42 AM.

      Comment


      • #4
        First, the "CR" in PCR stands for "Chain Reaction". That is each new product strand created in one cycle becomes a potential template strand for subsequent cycles. Hence, it is theoretically possible that the number of amplified molecules will double each cycle. So 18 cycles could result in 2^18 (two raised to the eighteenth power) fold increase in the amount of template initially present. That is roughly a 500 thousand fold increase in the initial amount of template. Not 18x.

        Well, I'll just leave it that, for now.

        --
        Phillip

        Comment


        • #5
          Hi Phillip,
          thank you for your reply. That's part is what I am confused about. Since we have so many replicates of the original templates. I assume we should see a lot of duplicate reads for that amplified templates. Why do people always say, we should only see a small portion of duplicate reads?
          Thanks.
          -Q

          Comment


          • #6
            Well how many total sequence reads did you generate?

            --
            Phillip

            Comment


            • #7
              Originally posted by qiudao View Post
              Hi Phillip,
              thank you for your reply. That's part is what I am confused about. Since we have so many replicates of the original templates. I assume we should see a lot of duplicate reads for that amplified templates. Why do people always say, we should only see a small portion of duplicate reads?
              Thanks.
              -Q

              As for why you shouldn't see a lot of duplicate reads, consider the size of your genome vs. the number of sequence tags. If you assume random shearing and equal recovery of every fragment, then you're sampling only a subset of the fragments (so duplicates should be rare).

              PCR does generate duplicates; however, consider the number of molecules you're sequencing vs. the number of molecules in your library. Again, you're sampling only a small subset of the total.

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              • #8
                There are two different PCR reactions involved in most sequencing technologies. Figure out when they occur and you will have your answer.

                Comment


                • #9
                  Hi HESmith,

                  That's the answer I am looking for. Thank you very much.
                  Thank you pmiguel too.
                  the PCR actually increase the chance of sampling whole population (individual read).

                  -Q

                  Comment


                  • #10
                    Originally posted by qiudao View Post
                    .
                    the PCR actually increase the chance of sampling whole population (individual read).

                    -Q
                    No, that's not correct. If anything, the fewer fragments you have, the more likely you will sequence the whole population. What PCR does do is help ensure that you submit the correct amount of properly prepared DNA for the sequencing itself to function optimally, and for some applications it helps you enrich for the types of fragments that you specifically want to sequence.

                    Comment


                    • #11
                      Originally posted by Heisman View Post
                      No, that's not correct. If anything, the fewer fragments you have, the more likely you will sequence the whole population. What PCR does do is help ensure that you submit the correct amount of properly prepared DNA for the sequencing itself to function optimally, and for some applications it helps you enrich for the types of fragments that you specifically want to sequence.
                      It also moves you out of the alien sub-nanogram "90% of my sample bound to the plastic in my pipette tip" realm into the more familiar microgram realm where I have plenty of sample to spare.

                      --
                      Phillip

                      Comment


                      • #12
                        Hesiman,
                        Sorry for the confusion, the "whole population", I actually mean the whole genome we tried to sequence or the target region we tried to sequence. Thank you for your clarification anyway.

                        Comment


                        • #13
                          Originally posted by qiudao View Post
                          Hi Guys,
                          I am doing some chip-seq assay.
                          Poor yielding reactions are the problem with Chip-seq(Chromatin Immuno-precipitation sequencing). So even if the genome is huge, the amount that was recovered from that reaction is probably small, which you subsequently amplified.

                          Its like taking a 16 bit number modulo 256 multiplying the remainder by 256, sure it has approximately the same magnitude at the end, but you lost something.

                          Comment


                          • #14
                            Originally posted by rskr View Post
                            Its like taking a 16 bit number modulo 256 multiplying the remainder by 256, sure it has approximately the same magnitude at the end, but you lost something.
                            This will be really helpful for the person unclear on the limitations imposed by limited starting sample on a sequence data set, but adept at modulo arithmetic. Thanks rskr for providing clarity to this often overlooked minority! (If they exist at all, I suppose they would be reading this site...)

                            --
                            Phillip

                            Comment


                            • #15
                              Originally posted by pmiguel View Post
                              This will be really helpful for the person unclear on the limitations imposed by limited starting sample on a sequence data set, but adept at modulo arithmetic. Thanks rskr for providing clarity to this often overlooked minority! (If they exist at all, I suppose they would be reading this site...)

                              --
                              Phillip
                              Ah tough crowd. For my next topic I will address why log ratios amplify noise in the expressions near zero.

                              Comment

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