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Originally posted by rskr View PostIts like taking a 16 bit number modulo 256 multiplying the remainder by 256, sure it has approximately the same magnitude at the end, but you lost something.
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Phillip
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Originally posted by qiudao View PostHi Guys,
I am doing some chip-seq assay.
Its like taking a 16 bit number modulo 256 multiplying the remainder by 256, sure it has approximately the same magnitude at the end, but you lost something.
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Hesiman,
Sorry for the confusion, the "whole population", I actually mean the whole genome we tried to sequence or the target region we tried to sequence. Thank you for your clarification anyway.
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Originally posted by Heisman View PostNo, that's not correct. If anything, the fewer fragments you have, the more likely you will sequence the whole population. What PCR does do is help ensure that you submit the correct amount of properly prepared DNA for the sequencing itself to function optimally, and for some applications it helps you enrich for the types of fragments that you specifically want to sequence.
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Phillip
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Originally posted by qiudao View Post.
the PCR actually increase the chance of sampling whole population (individual read).
-Q
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Hi HESmith,
That's the answer I am looking for. Thank you very much.
Thank you pmiguel too.
the PCR actually increase the chance of sampling whole population (individual read).
-Q
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There are two different PCR reactions involved in most sequencing technologies. Figure out when they occur and you will have your answer.
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Originally posted by qiudao View PostHi Phillip,
thank you for your reply. That's part is what I am confused about. Since we have so many replicates of the original templates. I assume we should see a lot of duplicate reads for that amplified templates. Why do people always say, we should only see a small portion of duplicate reads?
Thanks.
-Q
As for why you shouldn't see a lot of duplicate reads, consider the size of your genome vs. the number of sequence tags. If you assume random shearing and equal recovery of every fragment, then you're sampling only a subset of the fragments (so duplicates should be rare).
PCR does generate duplicates; however, consider the number of molecules you're sequencing vs. the number of molecules in your library. Again, you're sampling only a small subset of the total.
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Hi Phillip,
thank you for your reply. That's part is what I am confused about. Since we have so many replicates of the original templates. I assume we should see a lot of duplicate reads for that amplified templates. Why do people always say, we should only see a small portion of duplicate reads?
Thanks.
-Q
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First, the "CR" in PCR stands for "Chain Reaction". That is each new product strand created in one cycle becomes a potential template strand for subsequent cycles. Hence, it is theoretically possible that the number of amplified molecules will double each cycle. So 18 cycles could result in 2^18 (two raised to the eighteenth power) fold increase in the amount of template initially present. That is roughly a 500 thousand fold increase in the initial amount of template. Not 18x.
Well, I'll just leave it that, for now.
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Phillip
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ECO,
I have done PCR for years. But I still don't know what I was missing.
PCR was used to amplify template, and this is not a random priming; and of course, the final result will contain similar copies of template, i.e for every template which was amplified should have at least one duplicate read. Why people said we should see very small amount of duplicate reads?
Could you elaborate on this? Really confused.
Thank you.
-QLast edited by qiudao; 10-18-2011, 07:42 AM.
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how were the duplicate reads generated?
Hi Guys,
I am doing some chip-seq assay. I am wondering how the duplicate reads were generated.
I know the sonication will generate random fragments. However, there is a step of 18 cycles PCR to amplify the library DNA. So, for each fragment, there should be 18 copies. i.e. each fragments should be ideally duplicate 18 times. If this is the case, why we need to remove them? and why we generally can not see 18 copies of the same reads after mapping?
Thank you.
-QTags: None
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