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  • zorph
    Member
    • May 2010
    • 40

    #1

    running samtools in shell script

    hi
    I am trying to run this shell script
    Code:
    for a in {seq 1 22}
    samtools view -h file.bam | awk '$3=="chr$a" || /^@/' | samtools view -S - -b -o Chr$a.bam
    done
    when I do it on the command line it works like a charm, but when i try to throw it in a shell it doesn't give any output. Any ideas?
  • dpryan
    Devon Ryan
    • Jul 2011
    • 3478

    #2
    You should specify whether you're using bash, tcsh, or something else. I recall that for bash your syntax is wrong. Also, I imagine you should escape the $3 since that could otherwise cause some issues.

    Comment

    • Alex Renwick
      Member
      • Jul 2011
      • 44

      #3
      I don't have any help for why your script didn't run, but I can tell you that
      samtools can do what you want by itself.

      Code:
      for a in {1..22}; do 
        samtools view -b file.bam chr$a -o Chr$a.bam
      done
      Or, better yet, pipe the result of that "samtools view file region" command to the next step of the analysis instead of creating a bunch of new bam files.

      Comment

      • zorph
        Member
        • May 2010
        • 40

        #4
        HTML Code:
        You should specify whether you're using bash, tcsh, or something else. I recall that for bash your syntax is wrong. Also, I imagine you should escape the $3 since that could otherwise cause some issues.
        i am using bash. The entire command is below:
        Code:
        for a in {1..22}
        do
              samtools view -h AD3.sorted.bam | awk '$3=="chr$a" || /^@/' | samtools view -S - -b -o chr$a.bam
        done
        Last edited by zorph; 03-02-2012, 06:35 AM.

        Comment

        • Alex Renwick
          Member
          • Jul 2011
          • 44

          #5
          For me, the awk command doesn't work even from the command line. The single quotes prevent bash from expanding "chr$a" to (e.g.) "chr1". Awk is looking for the third column to literally match "chr$a".

          I did this to get the awk command to work:

          Code:
          awk -v a=$a '$3==sprintf("chr%s",a) || /^@/ '

          Comment

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