In BASH splitting into substring based on pattern(or) last occurrence of a digit (**)

[AnushaC]

Hi,

I am trying to split string into substring based on pattern in bash (or) based on last occurance of a digit
y=`echo "AB097865ATCTCTAGCAGTGGCGCCCGAACAGGGCACGCGAA"|grep "[AT|AC|AG|AA|CT|CC|CA|CG|GT|GC|GA|GG|TT|TC|TA|TG]"`

I tried to do like this but failed

I want to get the substring after the last digit and
result should be

ATCTCTAGCAGTGGCGCCCGAACAGGGCACGCGAA

Thanks so much for help

Anusha

[Richard Finney]

ugly way ... pick a character not in the input, in this case '_' ...
y=`echo "AB097865ATCTCTAGCAGTGGCGCCCGAACAGGGCACGCGAA" | sed 's/[0-9]/_/g' | awk -F "_" '{print $NF}'`
echo $y

better (I think) ..

y=`echo "AB097865ATCTCTAGCAGTGGCGCCCGAACAGGGCACGCGAA" | sed 's/.*[0-9]//g' `
echo $y

[westerman]

I have always thought that invoking sed/awk or any of the other programming tools for work inside Bash is ..., well, cheating. Useful in the practical "let us get stuff done" sense but at that point one might as just well write Perl or Python, etc. code. 'sort', 'cut', 'grep' are valid tools within a script since they are not really programming.

Anyway to the OP, look at:

http://tldp.org/LDP/abs/html/string-manipulation.html

It has an example of what you want to do.

[tomc]

Variable substitution

foo="AB097865ATCTCTAGCAGTGGCGCCCGAACAGGGCACGCGAA"
echo ${foo##*[0-9]}
ATCTCTAGCAGTGGCGCCCGAACAGGGCACGCGAA