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  • JQL
    Member
    • Apr 2011
    • 83

    #1

    bash shell question

    I tried to do a simple task in batch--unzipping many gz files. I have many .gz files, but how come it only unzipped one file then finished? Anything wrong with my script? thanks. John


    ## unzip fastq.gz
    for i in *.fastq.gz
    do
    #echo $i
    zcat "$i" > "${i%.*}"
    done
  • azneto
    Member
    • Dec 2009
    • 24

    #2
    have you tried 'gunzip *.fastq.gz' ?

    Comment

    • JQL
      Member
      • Apr 2011
      • 83

      #3
      gunzip *.fastq.gz will delete original gz files. i want to keep original files.



      Originally posted by azneto View Post
      have you tried 'gunzip *.fastq.gz' ?

      Comment

      • azneto
        Member
        • Dec 2009
        • 24

        #4
        for i in `ls *.fastq.gz`; do gunzip -c $i > $i.fastq; done

        Comment

        • JQL
          Member
          • Apr 2011
          • 83

          #5
          I tried
          for i in `ls *.fastq.gz`; do gunzip -c $i > ${i%.gz}; done

          still only unzipped just first file then finished. no error. very strange.


          Originally posted by azneto View Post
          for i in `ls *.fastq.gz`; do gunzip -c $i > $i.fastq; done

          Comment

          • azneto
            Member
            • Dec 2009
            • 24

            #6
            I tested your version of the command and it worked fine. It could be something related to permissions.

            Comment

            • JQL
              Member
              • Apr 2011
              • 83

              #7
              thanks. I thought it might be related to something internal. will find out.

              Originally posted by azneto View Post
              I tested your version of the command and it worked fine. It could be something related to permissions.

              Comment

              • Richard Finney
                Senior Member
                • Feb 2009
                • 701

                #8
                for i in $(ls *.gz); do sn=`echo $i | sed 's/\.gz$//'`; zcat $i > $sn; done;

                Comment

                • JQL
                  Member
                  • Apr 2011
                  • 83

                  #9
                  another nice way to do it.

                  I really think something is going on with my server. It still finished after doing one file. I will ask my admin tomorrow. Will let you know.

                  By any chance did this happen to any one of you here?

                  Originally posted by Richard Finney View Post
                  for i in $(ls *.gz); do sn=`echo $i | sed 's/\.gz$//'`; zcat $i > $sn; done;

                  Comment

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