Announcement

Collapse
No announcement yet.
X
 
  • Filter
  • Time
  • Show
Clear All
new posts

  • maubp
    replied
    This was partly why the SAM/BAM spec wording was changed from insert size to fragment size.

    Leave a comment:


  • rskr
    replied
    Lets all do ourselves a favor and refer to the total length of a pairs from end to end as the fragment length(start of the first pair on the reference to the end of the second pair including all bases in either of the reads), and refer to the the space between as the "space between the pairs" or every base which wasn't sequenced of the fragment. That way there will be no confusion. And ignore any attempts to define insert size, which will inevitably be misconstrued by whom ever you are trying to 'splain it.

    Leave a comment:


  • spapillon
    replied
    Make sure you adjust the standard deviation parameter accordingly when trimming out the adapters/barcodes and poor quality ends.

    Leave a comment:


  • Heisman
    replied
    Originally posted by catbus View Post
    It would be nice to have an authoritative answer here, since the commentators above appear to disagree.

    > e.g. for paired end runs with fragments selected at 300bp, where each end is 50bp, you should set -r to be 200.

    If you have two 50bp paired-end files, and the original fragment was 300 bp, then the result is (300 - 50 - 50 = 200).

    But: is the adapter included in the fragment size? I am getting the impression that it should NOT be included. However, I am not 100% sure.
    Insert size typically means without any universal/barcoded adapter sequence attached. When considering long barcodes where the length actually matters the definition may get a bit hazy.

    Leave a comment:


  • catbus
    replied
    It would be nice to have an authoritative answer here, since the commentators above appear to disagree.

    > e.g. for paired end runs with fragments selected at 300bp, where each end is 50bp, you should set -r to be 200.

    If you have two 50bp paired-end files, and the original fragment was 300 bp, then the result is (300 - 50 - 50 = 200).

    But: is the adapter included in the fragment size? I am getting the impression that it should NOT be included. However, I am not 100% sure.

    Leave a comment:


  • elizzybethy
    replied
    I subtract the adapter length and the read lengths from the final average library fragment size when I use the TopHat -r option, because that is how it makes sense to me.


    Originally posted by frymor View Post
    Hi elizzybethy



    According to the description on the tophat manual the option -r is:


    So if I understand it correctly, I only need to subtract the reads length without taking into account the adapters (or in your examples only 500-(76*2), without the 119bo aapter length).

    Is this correct?

    Leave a comment:


  • kmcarr
    replied
    Originally posted by frymor View Post
    Hi elizzybethy



    According to the description on the tophat manual the option -r is:
    -r/--mate-inner-dist <int> This is the expected (mean) inner distance between mate pairs. For, example, for paired end runs with fragments selected at 300bp, where each end is 50bp, you should set -r to be 200. There is no default, and this parameter is required for paired end runs.
    So if I understand it correctly, I only need to subtract the reads length without taking into account the adapters (or in your examples only 500-(76*2), without the 119bo aapter length).

    Is this correct?
    O.K. I just redacted my post in case anyone saw in within the few minutes it was up. I realized that I misread fymor's post (reading as "with" where it said "without".
    Last edited by kmcarr; 01-11-2011, 06:47 AM.

    Leave a comment:


  • frymor
    replied
    Hi elizzybethy

    Originally posted by elizzybethy View Post
    I think that people in general use different terms for the distance BETWEEN the sequenced ends of an insert. For instance, the -r option in TopHat is for "mate inner distance", which in this example would be 500-119-(76*2) I believe.
    According to the description on the tophat manual the option -r is:
    -r/--mate-inner-dist <int> This is the expected (mean) inner distance between mate pairs. For, example, for paired end runs with fragments selected at 300bp, where each end is 50bp, you should set -r to be 200. There is no default, and this parameter is required for paired end runs.
    So if I understand it correctly, I only need to subtract the reads length without taking into account the adapters (or in your examples only 500-(76*2), without the 119bo aapter length).

    Is this correct?

    Leave a comment:


  • elizzybethy
    replied
    I think that most people define it as Chipper describes. So if you are doing Illumina PE sequencing, it would be the approximate size of the band you cut out of the gel or measured on a bioanalyzer at the end of library prep minus 119 bp, because the total adapter length on one side for Illumina is 58 bp and the other side is 61bp.

    If your sample aligns pretty well, you wouldn't have to specify the -a option in bwa though, and keep in mind that the bwa -a option is the MAX insert size not the AVERAGE insert size if you do specify it, so in this example you would want it to be quite a bit greater than 500-119, depending on the width of your library fragment size distribution.

    I think that people in general use different terms for the distance BETWEEN the sequenced ends of an insert. For instance, the -r option in TopHat is for "mate inner distance", which in this example would be 500-119-(76*2) I believe.

    Leave a comment:


  • Chipper
    replied
    It is 500 minus the total length of adaptors, unless you size-selected your sample before doing the library prep.

    Leave a comment:


  • Graham Etherington
    started a topic Technically, what is 'insert-size'?

    Technically, what is 'insert-size'?

    I've become slightly confused as to the use of the word 'insert-size' so I was wondering if someone could just confirm that my understanding of the term is correct.

    If the fragment size excised from the gel is 500 base pairs and I'm doing 76bp paired-end sequencing, is my insert size (say for use in the -a option in bwa sampe) 500 or 348 (500 - (2*76))?

    Many thanks.

Latest Articles

Collapse

  • seqadmin
    Multiomics Techniques Advancing Disease Research
    by seqadmin


    New and advanced multiomics tools and technologies have opened new avenues of research and markedly enhanced various disciplines such as disease research and precision medicine1. The practice of merging diverse data from various ‘omes increasingly provides a more holistic understanding of biological systems. As Maddison Masaeli, Co-Founder and CEO at Deepcell, aptly noted, “You can't explain biology in its complex form with one modality.”

    A major leap in the field has
    ...
    02-08-2024, 06:33 AM

ad_right_rmr

Collapse

News

Collapse

Topics Statistics Last Post
Started by seqadmin, Yesterday, 08:52 AM
0 responses
30 views
0 likes
Last Post seqadmin  
Started by seqadmin, 02-20-2024, 08:57 AM
0 responses
18 views
0 likes
Last Post seqadmin  
Started by seqadmin, 02-14-2024, 09:19 AM
0 responses
52 views
0 likes
Last Post seqadmin  
Started by seqadmin, 02-12-2024, 03:37 PM
0 responses
443 views
0 likes
Last Post seqadmin  
Working...
X