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  • Error while python code terse

    Hi Members,

    I am having a hard time with python code, making it terse. One liners. I see a lot on stackoverflow using lambda. I am unable to cope up with it.

    Would really appreciate any input in this regard.

    So here is how I am running the file.
    python read_pdb_file.py 1iw6.pdb 1m0l.pdb
    Code:
    def checkExtension2(*file_name):
    # trying to shrink the code..
        [print i+" doesn't end with .pdb" for i in file_name if not i.endswith(".pdb")]
    
    
    def checkExtension(*file_name): # this runs fine
        for i in file_name: 
            if not i.endswith(".pdb"):
                print i+" doesn't end with .pdb"
                sys.exit(1)
    
    if __name__=="__main__":
        checkExtension2(sys.argv[1],sys.argv[2])
    Error:
    [print i+" doesn't end with .pdb" for i in file_name if not i.endswith(".pdb")]
    ^
    SyntaxError: invalid syntax

    Please advise.
    Bioinformaticscally calm

  • #2
    It doesn't know what to do with the print inside the list comprehension.

    If you really want it in one line, how about:

    To print the first one:
    Code:
    print [i+" doesn't end with .pdb" for i in file_name if not i.endswith(".pdb")][0]
    To print all:
    Code:
    print '\n'.join([i+" doesn't end with .pdb" for i in file_name if not i.endswith(".pdb")])
    Last edited by cliffbeall; 10-22-2014, 10:52 AM. Reason: To put in 2nd case

    Comment


    • #3
      Thanks for replying.
      Could you please elaborate why and what is happening?
      I work a lot on file parsing. A lot of code is to check/verfify, and I want to polish my coding on them.
      Bioinformaticscally calm

      Comment

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