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  • lynchde
    Junior Member
    • Oct 2011
    • 6

    One gene dominates RNAseq

    Hi all,

    Our lab recently performed RNAseq on bacteria, and found that 70-80% of the ribo-depleted reads come from one particular region of the genome in question. It's not any of the common house-keeping genes but something novel. It's also not a sequencing artifact, as we see it with qPCR.

    We have now generated a knock-out of this region and are trying to determine the best way to assess differential expression in this knock-out versus the wild-type strain. We have arrays (preferential) but can also do RNAseq if necessary. The concern is as follows. Given that in the wild-type strain, 70-80% of the ribo-depleted RNA comes from this one region, then only 20-30% of the RNA will be from the remainder of the genome. Whereas in the knock-out, 100% of the RNA will be the remainder of the genome. So the question is how best to compare a sample of 20-30% to 100%.

    Our options are as follows:
    1) using 2 colour arrays with 4x as much RNA from the wild-type strain over the knock-out, to hopefully compensate for the dominance in the wild-type by the one region
    2) use separate 1 colour arrays, and try to normalize by housekeeping genes.
    3) RNAseq, using 4x number of reads allowed for wild-type strain over knock-out.

    I know there are bioinformatical approaches for normalization, but many assume ~ 1:1 amounts of RNA in samples. So I guess I have multiple questions.
    a) Can we get away with a 2 colour array of 4x the amount of cDNA on one over the other?
    b) If so, what's the best way to normalize in that situation, when it's not definitely 1:1 ratio of input RNA?
    c) Are there any other issues I need to be concerned about if I take this approach, or if we resort to RNAseq?

    Any suggestions would be greatly appreciated!
    Thank you!
  • jparsons
    Member
    • Feb 2012
    • 62

    #2
    I would advocate for spike-in based normalization in this case. If you put spike-ins at 1:1, you can scale the remainder of reads accordingly. See Revisiting global gene expression analysis. Cell. 2012 Oct 26;151(3):476-82. doi: 10.1016/j.cell.2012.10.012.

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