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  • Golsheed
    Member
    • Oct 2014
    • 49

    #1

    log2FoldChange in DESeq2

    Hello,
    I have some trouble understanding how the log2FoldChange is calculated in DESeq2? Assuming that the full model is ~ AF + Condition, I'm interested in the log2FoldChange of the raw counts with respect to the covariate Condition (which is a factor with two levels).
    I was under the impression that its calculated as the log2 of the ratio of mean of the normalized counts in the two levels. However, this is not what I get from DESeq2. Could someone please give me a hint on how these values are actually calculated?
    Or is there a way I can get an estimate (or values close the log2FoldChange obtained from DESeq2) without using DESeq2?
    Thanks,
    Golsheed
  • fanli
    Senior Member
    • Jul 2014
    • 197

    #2
    Are you looking at the moderated fold changes or the unshrunken MLEs? See section 1.4.1:
    The Bioconductor project aims to develop and share open source software for precise and repeatable analysis of biological data. We foster an inclusive and collaborative community of developers and data scientists.


    You may want to do something like this to get the actual log2FoldChange values:
    Code:
    resMLE <- results(dds, addMLE=T)

    Comment

    • Michael Love
      Senior Member
      • Jul 2013
      • 333

      #3
      In a previous thread, I answered one of your questions with " log2FoldChange with betaPrior=FALSE .... is the log2 ratio of the mean of normalized counts"

      The default is to use a prior on the log2 fold change and give an estimate using the posterior distribution of log2 fold change.

      See the paper for full details:



      ...or check the help files: ?nbinomWaldTest.

      If you use betaPrior=FALSE, then no beta prior is used. If you use addMLE=TRUE as fanli suggests, then a beta prior is used, but a column is added to the results table which gives the unshrunken estimate of log2 fold change which is mean(normalized counts)/mean(normalized counts). See ?results for full details on this.

      Comment

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