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  • pmiguel
    replied
    Originally posted by happy View Post
    How many genomes (human haploid) are in a ug of DNA?
    How about the chicken haploid genome instead? That is 1 billion bp.

    If 1 ug of 1 thousand bp fragments is 1 trillion molecules, that is the same as saying that a quadrillion bp genome (1 thousand x 1 trillion = 1E+03 x 1E+12 = 1E+15 = 1 quadrillion) is 1 ug.

    So:

    Code:
    genome             genome
    size (bp) 	   mass
    -------------------------------
    1 quadrillion 	   1 ug
    1 trillion 	   1 ng
    1 billion 	   1 pg
    1 million          1 fg
    So a haploid chicken genome is 1 pg. 1 million haploid chicken genomes are in a ug of chicken DNA.

    That means a haploid human genome is 3 pg. So 1 ug of human DNA is roughly 333,333 human genomes.

    --
    Phillip

    Leave a comment:


  • happy
    replied
    How many genomes (human haploid) are in a ug of DNA?

    Leave a comment:


  • pmiguel
    replied
    Originally posted by McTomo View Post
    If you multiply the losses in each step of the library preparation process (starting at the blunting), you come to the ~10% of the starting DNA ending up in the 454 library. Even though the PCR product was used, it has to be repaired: overhanging A's have to be removed and the phosphates have to be added. However, I agree that there might to be other types of damage that appear in the sheared genomic DNA that can't be repaired.
    Yes, my guess is that non-enzymatic fragmentation methods produce some ends that cannot be repaired by the typical T4-polymerase/T4-PNK. I posted my speculation on this topic, based largely on a very old paper:

    http://seqanswers.com/forums/showthread.php?t=2759


    The upshot was that sonication predominantly broke C-O bonds. While these C-O breaks may proceed through solvolysis to C-OH ends, other outcomes are conceivable. Unclear what ends nebulization/hydroshearing produce.

    While an unrepairable end, on either end, of a DNA fragment will prevent creation of a library amplicon from that fragment, there are other issues to consider. DNA damage may prevent replication of a DNA strand. How damaged is the typical DNA prep? I'm sure this has been considered in the literature. But a PCR reaction, lacking the support of a cellular environment, would be much more susceptible to chain-terminating DNA damage than an in vivo assay would detect.

    I think this is why the SOLiD protocols invariably utilize a pre-ePCR, PCR step. That way amplifiable library molecules will predominate in a sample and assays of that pre-amplified sample will more accurately predict that sample's behavior in ePCR.

    --
    Phillip

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  • McTomo
    replied
    Originally posted by pmiguel View Post
    A couple of notes. This paper only deals with post adaptor ligation DNA loss, because it starts with a PCR product/library molecule. Also, even the 99% potential loss of this step only explains 2 of the >6 orders of magnitude of DNA loss in the Roche protocol.
    If you multiply the losses in each step of the library preparation process (starting at the blunting), you come to the ~10% of the starting DNA ending up in the 454 library. Even though the PCR product was used, it has to be repaired: overhanging A's have to be removed and the phosphates have to be added. However, I agree that there might to be other types of damage that appear in the sheared genomic DNA that can't be repaired.

    Leave a comment:


  • pmiguel
    replied
    Originally posted by McTomo View Post
    In the figure 2 of this paper you can see where does you DNA go and the efficiency of each step in the 454 library preparation process:

    There seem to be the biggest loss at the NaOH melting step
    Thanks, that is very interesting. I knew about the highly variable and generally extremely low yields from the library immobilization/ssDNA elution. Bruce Roe's lab, for example, discards that step altogether. But the Maricic and Paabo method does make it seem much more attractive.

    A couple of notes. This paper only deals with post adaptor ligation DNA loss, because it starts with a PCR product/library molecule. Also, even the 99% potential loss of this step only explains 2 of the >6 orders of magnitude of DNA loss in the Roche protocol.

    As I've mentioned before I think most of the rest is probably the result of un-repairable ends and DNA damage that has rendered a given strand un-replicatable.

    --
    Phillip

    Leave a comment:


  • McTomo
    replied
    In the figure 2 of this paper you can see where does you DNA go and the efficiency of each step in the 454 library preparation process:

    There seem to be the biggest loss at the NaOH melting step

    Leave a comment:


  • pmiguel
    replied
    Originally posted by What_Da_Seq View Post
    How many single/di/trinucleotides are being generated by the fragmentation process - invisible to visualization and percent DNA lost in the fragment sizing step. Philip I get your line of inquiry and I am wondering if single molecule sequencing improves on the abysmal efficiency.
    My 1.25 cent
    Depends on the method. Nebulization/Hydroshear probably produces very few oligomers. But size selection will drastically reduce the amount of DNA. Still this usually is not much more than 90% loss.

    My guess is that the majority of the subsequent loss is a result of (1)Unrepairable ends and (2)DNA damage that prevents DNA replication.

    --
    Phillip

    Leave a comment:


  • What_Da_Seq
    replied
    How many single/di/trinucleotides are being generated by the fragmentation process - invisible to visualization and percent DNA lost in the fragment sizing step. Philip I get your line of inquiry and I am wondering if single molecule sequencing improves on the abysmal efficiency.
    My 1.25 cent

    Leave a comment:


  • pmiguel
    replied
    Yes, I de-emphasized this point in my original post, because it has received some attention and methods have been developed to address part of this particular issue. (Doing QC on the size distribution of a library you cannot see on a gel or lab chip would still be tricky.)

    Note, however that both papers appear to suffer from the same dismal molecular yields of "input DNA" to "library molecules".

    In the Meyer's paper, the Bonobo sample (table 2) starts with 500 ng and a mean fragment size of 500 bases. Using the "1 ug of 1kb DNA is about 1 trillion molecules" rule of thumb I suggested earlier -- that equals 1 trillion 500 base molecules (double stranded). Meyers succeeds in isolating 50,000 beads after enrichment from 1 trillion molecules he started with.

    Molecular yield: 5E+04/1E+12 = 5E-08
    that is, 0.000005%

    That yield is a 3x overestimate if you only count sequence-pass reads generated.

    Similarly, if you look at "additional file 2" in the White paper, the lowest input DNA amount used in a shotgun library is 0.7 ug of 550 bp mean size. Again over 1 trillion molecules to start with. This yielded 7E+05 to 1E+06 ssDNA library molecules (depending on quantitation method). That is an excellent molecular yield: 0.0001%. I still would like to know where most of the 99.9999% of the molecules went, though..

    But both papers show that trillions of library molecules are not necessary to get a good emulsion PCR. That is pretty well accepted these days.

    White et al. http://www.biomedcentral.com/1471-2164/10/116 do at least point in the direction of the 500 pound gorilla:

    It is natural to expect that library preparation protocols developed with the capacity to handle up to five micrograms of input are far from optimal with respect to minimizing loss from nanogram or picogram samples. A procedure optimized for trace samples with reduced reaction volumes and media quantities, possibly formatted in a microfluidic chip, has the potential to dramatically improve the recovery of library molecules, allowing preparation of sequencing libraries from quantities of sample comparable to that actually required for the sequencing run, e.g. close to or less than one picogram.
    --
    Phillip

    Leave a comment:


  • krobison
    replied
    Check out these papers: each would suggest that the "I need enough DNA to visualize" angle is why so much input DNA; you apparently can get by with very little DNA if you have a better way to track it & quantitate it.

    Anyone here routinely using these protocols or similar ones? How do they really behave?


    BMC Genomics. 2009 Mar 19;10:116.
    Digital PCR provides sensitive and absolute calibration for high throughput sequencing.
    White RA 3rd, Blainey PC, Fan HC, Quake SR.

    Department of Bioengineering at Stanford University and Howard Hughes Medical Institute, Stanford, CA 94305, USA. [email protected]
    BACKGROUND: Next-generation DNA sequencing on the 454, Solexa, and SOLiD platforms requires absolute calibration of the number of molecules to be sequenced. This requirement has two unfavorable consequences. First, large amounts of sample-typically micrograms-are needed for library preparation, thereby limiting the scope of samples which can be sequenced. For many applications, including metagenomics and the sequencing of ancient, forensic, and clinical samples, the quantity of input DNA can be critically limiting. Second, each library requires a titration sequencing run, thereby increasing the cost and lowering the throughput of sequencing. RESULTS: We demonstrate the use of digital PCR to accurately quantify 454 and Solexa sequencing libraries, enabling the preparation of sequencing libraries from nanogram quantities of input material while eliminating costly and time-consuming titration runs of the sequencer. We successfully sequenced low-nanogram scale bacterial and mammalian DNA samples on the 454 FLX and Solexa DNA sequencing platforms. This study is the first to definitively demonstrate the successful sequencing of picogram quantities of input DNA on the 454 platform, reducing the sample requirement more than 1000-fold without pre-amplification and the associated bias and reduction in library depth. CONCLUSION: The digital PCR assay allows absolute quantification of sequencing libraries, eliminates uncertainties associated with the construction and application of standard curves to PCR-based quantification, and with a coefficient of variation close to 10%, is sufficiently precise to enable direct sequencing without titration runs.

    PMID: 19298667 [PubMed - indexed for MEDLINE]

    http://nar.oxfordjournals.org/cgi/pm...&pmid=18084031
    Nucleic Acids Res. 2008 Jan;36(1):e5. Epub 2007 Dec 15.
    From micrograms to picograms: quantitative PCR reduces the material demands of high-throughput sequencing.
    Meyer M, Briggs AW, Maricic T, Höber B, Höffner B, Krause J, Weihmann A, Pääbo S, Hofreiter M.

    Max Planck Institute for Evolutionary Anthropology, Deutscher Platz 6, D-04103 Leipzig, Germany. [email protected]
    Current efforts to recover the Neandertal and mammoth genomes by 454 DNA sequencing demonstrate the sensitivity of this technology. However, routine 454 sequencing applications still require microgram quantities of initial material. This is due to a lack of effective methods for quantifying 454 sequencing libraries, necessitating expensive and labour-intensive procedures when sequencing ancient DNA and other poor DNA samples. Here we report a 454 sequencing library quantification method based on quantitative PCR that effectively eliminates these limitations. We estimated both the molecule numbers and the fragment size distributions in sequencing libraries derived from Neandertal DNA extracts, SAGE ditags and bonobo genomic DNA, obtaining optimal sequencing yields without performing any titration runs. Using this method, 454 sequencing can routinely be performed from as little as 50 pg of initial material without titration runs, thereby drastically reducing costs while increasing the scope of sample throughput and protocol development on the 454 platform. The method should also apply to Illumina/Solexa and ABI/SOLiD sequencing, and should therefore help to widen the accessibility of all three platforms.

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  • pmiguel
    replied
    Originally posted by Joann View Post
    If that's the methodology, my question is

    So.....what genome ends up getting sequenced?
    Not sure I follow you.

    Leave a comment:


  • Joann
    replied
    genome?

    If that's the methodology, my question is

    So.....what genome ends up getting sequenced?

    Leave a comment:


  • pmiguel
    started a topic Where does all the DNA go?

    Where does all the DNA go?

    The standard Roche protocol for shotgun library construction asks for 10 ug of input DNA to yield a few million templated beads for sequencing. Rule of thumb: 1 ug of 1 kb double stranded DNA is 1 trillion (1E+12) molecules[1].

    Get that? 10 trillion molecules to start with so that I can sequence less than 10 million of them. What happened to the other 9,999,990,000,000 molecules?

    Not really fair to the Roche protocol? Usually one ends up with enough library to sequence more than 10 million bead? Plug your own numbers in. My guess is the molecular yield from this technique will be no better than 0.1%.

    I do not mean to single out Roche here, I think protocols for all instrument systems are looking at fractions of a percent molecular yield. As long as one has plenty of DNA, maybe it does not matter. But sometimes DNA (or RNA) is limiting, no?

    And what if there is bias in the loss process? Most of us sweat adding a few more cycles of PCR into our library prep procedure because we know PCR can bias our results. But I have never met a single person who worried that the 99.9% (add as many nines as you care to) of DNA molecules being lost during library construction might have a sequence-composition biased component to their loss.

    If I get any response (other than a blank stare) from those designing these protocols about the molecular yield, it usually that the yields in each step are not 100%. The implication, I presume, is that these yield losses are multiplicative. Fair enough, how many steps with 50% yield do I need to lose 99.9% of my DNA? That would be ten steps.

    I do not think most library construction steps have yields as low as 50%. Instead, I think it more likely that:

    (A) A few steps have extremely low molecular yields and

    (B) The protocols we are using rely on our being able to visualize the molecules and their size distribution for purposes of quality control.

    I am going to ignore (B) for the purposes of the rest of this post.

    As for (A), most of the methodologies I see being developed for low amounts of starting material are focused on amplification. Might be worth taking a look at where DNA (or RNA) is being lost and tightening that up. A couple of places to look would be % of ends successfully repaired after mechanical fragmentation of DNA and chemical DNA damage. The latter may be a non-issue or not. But think about it, how often do you worry about the redox-state of your DNA? How about UV damage from the sunlight streaming in through your lab windows?

    Might 90% of the molecules in a typical DNA prep be impossible to replicate without repair beyond the end repair we normally deploy? Could that number be 99% or 99.9%? Real question. I would like to know.

    --
    Phillip

    (Notes)
    1. Okay, yeah, using some standard numbers, like 650 MW for a base pair, the number is really 926 billion molecules, not 1 trillion. But nothing I discuss here would be sensitive to less than 10% tolerances, so the difference is safe to ignore...

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