So I have a DNA sample that's 330 base pairs in size with a concentration of 51 ng/ul. Can anyone walk me through how to make a 10 nm dilution?
-
-
Current concentration can be worked out as followsOriginally posted by KrispyKareme2 View Post
(ng/µL * 10^6) / 649 * bp)
649 is an estimate of the molecular weight of a double stranded base pair, so molecular weight of your DNA should be 214170 g/mol if the length is 330bp. The 10^6 is a conversion parameter as you need to convert between grams, nanograms, litres, microlitres, molar and nonomolars in the equation.
Your sample has an ~concentration of 238nM.
You can then work out your dilution from that, e.g. 2.1µL of sample plus 47.9µL of EB would give you 50µL of 10nM stock -
This calculator will take concentration in ng/ul and template length and calculate the dilution required to make stock nM solutions:
Comment
-
Hi Andrew!Comment
-
CRISPR/Cas9 sparked the gene editing revolution for both research and therapeutics.1 But this system still showed severe issues that limited its applications. The most prominent were the heavy reliance on PAM sequences, delivery limitations, double-stranded breaks that prompt unintended edits and cell death, and editing inefficiency (both in targeting and in knock-in reliability).
Despite this, “CRISPR helped turn genome editing from a specialized technique into...07-31-2026, 11:01 AM
Comment