So I have a DNA sample that's 330 base pairs in size with a concentration of 51 ng/ul. Can anyone walk me through how to make a 10 nm dilution?
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Current concentration can be worked out as followsOriginally posted by KrispyKareme2 View Post
(ng/µL * 10^6) / 649 * bp)
649 is an estimate of the molecular weight of a double stranded base pair, so molecular weight of your DNA should be 214170 g/mol if the length is 330bp. The 10^6 is a conversion parameter as you need to convert between grams, nanograms, litres, microlitres, molar and nonomolars in the equation.
Your sample has an ~concentration of 238nM.
You can then work out your dilution from that, e.g. 2.1µL of sample plus 47.9µL of EB would give you 50µL of 10nM stock -
This calculator will take concentration in ng/ul and template length and calculate the dilution required to make stock nM solutions:
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